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averaging an array

averaging an array

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jencalma	1 Jul, 2008 - 09:39 PM Post #1
New D.I.C Head Joined: 13 Jul, 2007 Posts: 46 My Contributions	Write a program that will accept your inputs and then compute the average of all the data. Now scan through the array to find the value that is farthest (lowest and highest) from the average. Sample Output: Input the data for the ten (10) internet cafes: data[ 0 ] = 600.2 data[ 1 ] = 625.0 data[ 2 ] = 512.5 data[ 3 ] = 125.7 data[ 4 ] = 216.1 data[ 5 ] = 367.4 data[ 6 ] = 855.5 data[ 7 ] = 235.5 data[ 8 ] = 1234.3 data[ 9 ] = 32586.4 average: 3735.86 Lowest: 125.7 Highest: 32586.4
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no2pencil	1 Jul, 2008 - 09:41 PM Post #2
Wet D.I.C. Joined: 10 May, 2007 Posts: 4,840 Thanked 27 times Dream Kudos: 2325 Expert In: Goofing Off My Contributions	Are you going to post all of your homework assignments here? Dream.In.Code has a policy by which we prefer to see a good faith effort on your part before providing source code for homework assignments. Please post the code you have written in an effort to resolve the problem, and our members would be happy to provide some guidance. Be sure to include a description of any errors you are encountering as well. Please post like this: Thank you for helping us helping you.
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captainhampton	2 Jul, 2008 - 06:00 AM Post #3
D.I.C Addict Joined: 17 Oct, 2007 Posts: 501 Thanked 2 times Dream Kudos: 775 My Contributions	no2pencil is right, we are more than willing to help however we want some genuine effort on your front.
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gabehabe	2 Jul, 2008 - 06:14 AM Post #4
T3H R0XX0R! Joined: 6 Feb, 2008 Posts: 2,300 Thanked 44 times Dream Kudos: 1450 Expert In: C, C++ My Contributions	Create an array of 10 floats. create two floats, hi=0; lo=999999 Create a float called total = 0 Loop 10 times to get input. During this loop, total += the input if input is higher than hi, hi = input if input is lower than lo, lo = input After the loop, float mean = total / 10 Hope this helps
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kapax	2 Jul, 2008 - 06:19 AM Post #5
New D.I.C Head Joined: 2 Jul, 2008 Posts: 33 Thanked 1 times My Contributions	Since nobody wants to write a code, I think it would really be inappropriate, too. You should code it by yourself. Here is the algorithm: 1) Get input, increment a counter X with each input received; 2) Make a loop repeating X times and sum up all the data; 3) Divide a sum by X - here you will get an average; To find farthest-lowest input from the average: 4) Make a simple linear search: save first element in some variable, let's say MIN; 5) Write a loop which would run X-1 times and if data[i] < MIN, then MIN = data[i]; Same with farthest-highest input. Got it?
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jencalma	4 Jul, 2008 - 02:32 AM Post #6
New D.I.C Head Joined: 13 Jul, 2007 Posts: 46 My Contributions	QUOTE(kapax @ 2 Jul, 2008 - 06:19 AM) Since nobody wants to write a code, I think it would really be inappropriate, too. You should code it by yourself. Here is the algorithm: 1) Get input, increment a counter X with each input received; 2) Make a loop repeating X times and sum up all the data; 3) Divide a sum by X - here you will get an average; To find farthest-lowest input from the average: 4) Make a simple linear search: save first element in some variable, let's say MIN; 5) Write a loop which would run X-1 times and if data[i] < MIN, then MIN = data[i]; Same with farthest-highest input. Got it? here is the code that i'm working on.. but i don't know how will i show which array is the lowest and highest. cpp #include<iostream.h> #include<conio.h> void name(); int main() { name(); float dat[10]; cout<<"\ninput data for ten(10) integers:"; cout<<"\ndata[0]="; cin>>dat[0]; cout<<"data[1]="; cin>>dat[1]; cout<<"data[2]="; cin>>dat[2]; cout<<"data[3]="; cin>>dat[3]; cout<<"data[4]="; cin>>dat[4]; cout<<"data[5]="; cin>>dat[5]; cout<<"data[6]="; cin>>dat[6]; cout<<"data[7]="; cin>>dat[7]; cout<<"data[8]="; cin>>dat[8]; cout<<"dats[9]="; cin>>dat[9]; float ave; float sum=0; for(int a=0;a<10;a++) { sum=sum+dat[a]; } ave=sum/10; cout<<"\naverage:"<<ave; getch(); } Mod Edit: Please
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gabehabe

4 Jul, 2008 - 03:23 AM

Post #7

T3H R0XX0R!

Joined: 6 Feb, 2008
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My Contributions

Your average does work, it's just that your program doesn't compile because you haven't defined your name() function.

cpp

#include<iostream>
#include<conio.h>

//void name();
// there is no definition to this function...
// what do you want it to do?

using namespace std; // cout, cin

int main()
{
//name();
float dat[10];
cout<<"\ninput data for ten(10) integers:";
cout<<"\ndata[0]=";
cin>>dat[0];
cout<<"data[1]=";
cin>>dat[1];
cout<<"data[2]=";
cin>>dat[2];
cout<<"data[3]=";
cin>>dat[3];
cout<<"data[4]=";
cin>>dat[4];
cout<<"data[5]=";
cin>>dat[5];
cout<<"data[6]=";
cin>>dat[6];
cout<<"data[7]=";
cin>>dat[7];
cout<<"data[8]=";
cin>>dat[8];
cout<<"dats[9]=";
cin>>dat[9];

float ave;
float sum=0;
for(int a=0;a<10;a++)
{
sum += dat[a];
}
ave=sum/10;
cout<<"\naverage:"<<ave;


getch();
}

Until I know what name is supposed to do, I can't help you with that.

Hope this helps

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Mallstrop	4 Jul, 2008 - 03:35 AM Post #8
New D.I.C Head Joined: 19 Jun, 2008 Posts: 32 Thanked 1 times My Contributions	Since the average is in the middle of the values, to get the furthest away from the average you're going to be after the minimum and maximum values. Once you have the min, max and the average you can compare them to see which is furthest from the average. To get the min/Max, Set min and max as dat[0] (It's the first one you see so you can compare against it.) Then in your for loop: if a value is bigger than Max, make that value your new Max if a value is less than Min, make that value your new Min. At the end of the for loop you have the values of Min and Max. You can compare them afterwards to see which is furthest from average.
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jencalma

4 Jul, 2008 - 05:20 AM

Post #9

New D.I.C Head

Joined: 13 Jul, 2007
Posts: 46

My Contributions

QUOTE(gabehabe @ 4 Jul, 2008 - 03:23 AM)

Your average does work, it's just that your program doesn't compile because you haven't defined your name() function.

cpp

#include<iostream>
#include<conio.h>

//void name();
// there is no definition to this function...
// what do you want it to do?

using namespace std; // cout, cin

int main()
{
//name();
float dat[10];
cout<<"\ninput data for ten(10) integers:";
cout<<"\ndata[0]=";
cin>>dat[0];
cout<<"data[1]=";
cin>>dat[1];
cout<<"data[2]=";
cin>>dat[2];
cout<<"data[3]=";
cin>>dat[3];
cout<<"data[4]=";
cin>>dat[4];
cout<<"data[5]=";
cin>>dat[5];
cout<<"data[6]=";
cin>>dat[6];
cout<<"data[7]=";
cin>>dat[7];
cout<<"data[8]=";
cin>>dat[8];
cout<<"dats[9]=";
cin>>dat[9];

float ave;
float sum=0;
for(int a=0;a<10;a++)
{
sum += dat[a];
}
ave=sum/10;
cout<<"\naverage:"<<ave;


getch();
}