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Using basic codes.

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Using basic codes.

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shangyi

1 Jul, 2008 - 02:47 AM

Post #1

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Joined: 15 Jun, 2008
Posts: 14

Windows

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Hello guys, i have a problem using C programming language, in this exercise. I am required to prompt user to enter a initial train station (A, B, C, D or E) and enter final train station (A, B, C, D or E) and calculate the total distance between the selected initial station and final station.

So what i did was i used the conditional statements if-else else-if to do it. And my basic idea was A=1, B=2, C=3, D=4, E=5 for the initial station and A=1, B=2, C=3, D=4, E=5 for the final station. Then i find the final minus initial to get the stations in between. Which is illustrated below:

A--B--C--D--E

So i used the conditional statements which worked fine.

cpp


#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <math.h>

int main()
{
	char start_station, end_station;
	int start_value, end_value, station_count;

	printf("Enter your initial station: ");
	scanf("%c", &start_station);
fflush(stdin);

	printf("Enter your final station: ");
	scanf("%c", &end_station);
fflush(stdin);

	if (start_station == 'A')
	{
		start_value = 1;
	printf("You have entered initial Station A\n");
	}
	else if (start_station == 'B')
	{
		start_value = 2;
		printf("You have entered initial Station B\n");
	}
	else if (start_station == 'C')
	{
		start_value = 3;
		printf("You have entered initial Station C\n");
	}
	else if (start_station == 'D')
	{
		start_value = 4;
		printf("You have entered initial Station D\n");
	}
	else if (start_station == 'E')
	{
		start_value = 5;
		printf("You have entered initial Station E\n");
	}
	else
	{
	printf("Invalid initial station entered.\n");
	}

	if (end_station == 'A')
	{end_value = 1;
	printf("You have entered last station: Station A\n");}

	else if (end_station == 'B')
	{end_value = 2;
	printf("You have entered last station: Station B\n");}
	
	else if (end_station == 'C')
	{end_value = 3;
	printf("You have entered last station: Station C\n");}
	
	else if (end_station == 'D')
	{end_value = 4;
	printf("You have entered last station: Station D\n");}
	
	else if (end_station == 'E')
	{end_value = 5;
	printf("You have entered last station: Station E\n");}
	
	else
	{
		printf("Invalid last station entered.\n");
	}

station_count = end_value - start_value;

	if (station_count < 0)
		station_count = -(station_count);
	else
station_count = station_count;

printf("\n\nTotal stations travelled : %d\n", station_count);


	return 0;
}

But I would like to ask, can i use an alternative method other than conditional statements? Because the exercise does not cover conditional statements, and i can't think of anything else except if-else else-if to do this.

Your help is greatly appreciated.

This post has been edited by shangyi: 1 Jul, 2008 - 03:20 AM

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gabehabe

1 Jul, 2008 - 03:11 AM

Post #2

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Joined: 6 Feb, 2008
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You could use a switch, like so:

cpp

#include <stdio.h>
#include <math.h>

int main()
{
    char start_station, end_station;
    int start_value, end_value, station_count;

    printf("Enter your initial station: ");
    scanf("%c", &start_station);
fflush(stdin);

    printf("Enter your final station: ");
    scanf("%c", &end_station);
fflush(stdin);

    switch (start_station)
    {
        case 'A':
            start_value = 1;
            printf("You have entered initial Station A\n");
        break;

        case 'B':
            start_value = 2;
            printf("You have entered initial Station B\n");
        break;

        case 'C':
            start_value = 3;
            printf("You have entered initial Station C\n");
        break;

        case 'D':
            start_value = 4;
            printf("You have entered initial Station D\n");
         break;

        case 'E':
            start_value = 5;
            printf("You have entered initial Station E\n");
            break;

        default:
            printf("Invalid initial station entered.\n");
	}


    switch (end_station)
    {
        case 'A':
            end_value = 1;
            printf("You have entered last station: Station A\n");
            break;

        case 'B':
            end_value = 2;
            printf("You have entered last station: Station B\n");
            break;

        case 'C':
            end_value = 3;
            printf("You have entered last station: Station C\n");
            break;

        case 'D':
            end_value = 4;
            printf("You have entered last station: Station D\n");
            break;

        case 'E':
            end_value = 5;
            printf("You have entered last station: Station E\n");
            break;

        default:
            printf("Invalid last station entered.\n");
    }

    station_count = end_value - start_value;

    if (station_count < 0)
        station_count = -(station_count);
    else
    station_count = station_count;

    printf("\n\nTotal stations travelled : %d\n", station_count);

    return 0;
}

Hope this helps

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shangyi

1 Jul, 2008 - 03:17 AM

Post #3

New D.I.C Head

Joined: 15 Jun, 2008
Posts: 14

Windows

My Contributions

QUOTE(gabehabe @ 1 Jul, 2008 - 03:11 AM)

You could use a switch, like so:

cpp

#include <stdio.h>
#include <math.h>

int main()
{
    char start_station, end_station;
    int start_value, end_value, station_count;

    printf("Enter your initial station: ");
    scanf("%c", &start_station);
fflush(stdin);

    printf("Enter your final station: ");
    scanf("%c", &end_station);
fflush(stdin);

    switch (start_station)
    {
        case 'A':
            start_value = 1;
            printf("You have entered initial Station A\n");
        break;

        case 'B':
            start_value = 2;
            printf("You have entered initial Station B\n");
        break;

        case 'C':
            start_value = 3;
            printf("You have entered initial Station C\n");
        break;

        case 'D':
            start_value = 4;
            printf("You have entered initial Station D\n");
         break;

        case 'E':
            start_value = 5;
            printf("You have entered initial Station E\n");
            break;

        default:
            printf("Invalid initial station entered.\n");
	}


    switch (end_station)
    {
        case 'A':
            end_value = 1;
            printf("You have entered last station: Station A\n");
            break;

        case 'B':
            end_value = 2;
            printf("You have entered last station: Station B\n");
            break;

        case 'C':
            end_value = 3;
            printf("You have entered last station: Station C\n");
            break;

        case 'D':
            end_value = 4;
            printf("You have entered last station: Station D\n");
            break;

        case 'E':
            end_value = 5;
            printf("You have entered last station: Station E\n");
            break;

        default:
            printf("Invalid last station entered.\n");
    }

    station_count = end_value - start_value;

    if (station_count < 0)
        station_count = -(station_count);
    else
    station_count = station_count;

    printf("\n\nTotal stations travelled : %d\n", station_count);

    return 0;
}

Hope this helps

Thanks for your reply but I'm not allowed to use switch too =(. im only allowed to use really basic things to do it

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gabehabe

1 Jul, 2008 - 03:43 AM

Post #4

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Joined: 6 Feb, 2008
Posts: 2,232

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How's this for lean and mean:

cpp

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <math.h>

int main()
{
	char start_station, end_station;

	printf("Enter your initial station: ");
	scanf("%c", &start_station);
    fflush(stdin);

	printf("Enter your final station: ");
	scanf("%c", &end_station);
    fflush(stdin);

    printf ("You chose %c as your starting position\n", start_station);
    printf ("You chose %c as your destination\n", end_station);

    station_count = start_station - end_station;
	if (station_count < 0)
        station_count = -(station_count);
    printf("\n\nTotal stations travelled : %d\n", station_count);

	return 0;
}

Hope this helps

This post has been edited by gabehabe: 1 Jul, 2008 - 03:44 AM

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shangyi

1 Jul, 2008 - 03:54 AM

Post #5

New D.I.C Head

Joined: 15 Jun, 2008
Posts: 14

Windows

My Contributions

QUOTE(gabehabe @ 1 Jul, 2008 - 03:43 AM)

How's this for lean and mean:

cpp

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <math.h>

int main()
{
	char start_station, end_station;

	printf("Enter your initial station: ");
	scanf("%c", &start_station);
    fflush(stdin);

	printf("Enter your final station: ");
	scanf("%c", &end_station);
    fflush(stdin);

    printf ("You chose %c as your starting position\n", start_station);
    printf ("You chose %c as your destination\n", end_station);

    station_count = start_station - end_station;
	if (station_count < 0)
        station_count = -(station_count);
    printf("\n\nTotal stations travelled : %d\n", station_count);

	return 0;
}

Hope this helps

oh my! This never crossed my mind... This piece of code tells me to minus the two character converted into integer form to get the number of stations right? Thanks dude! although if the first station is A and the second station is D.. then this might not work, but i owe u many thanks!

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gabehabe

1 Jul, 2008 - 05:10 AM

Post #6

T3H R0XX0R!

Joined: 6 Feb, 2008
Posts: 2,232

Windows

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Nope, it works...

I accidentally deleted the station_count declaration though

It checks the difference between the ASCII value, but be warned:
If the user enters A to d, the difference will be wrong... So we need to convert them to upper case, to avoid this problem, right?

cpp

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <math.h>
#include <ctype.h> // toupper()

int main()
{
	char start_station, end_station;
	int station_count;

	printf("Enter your initial station: ");
	scanf("%c", &start_station);
    fflush(stdin);

	printf("Enter your final station: ");
	scanf("%c", &end_station);
    fflush(stdin);

    // convert them to upper case to ensure ASCII math is correct
    start_station = toupper(start_station);
    end_station   = toupper(end_station);

    printf ("You chose %c as your starting position\n", start_station);
    printf ("You chose %c as your destination\n", end_station);

    station_count = start_station - end_station;
	if (station_count < 0)
        station_count = -(station_count);
    printf("\n\nTotal stations travelled : %d\n", station_count);

	return 0;
}

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shangyi

1 Jul, 2008 - 05:39 AM

Post #7

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Joined: 15 Jun, 2008
Posts: 14

Windows

My Contributions

QUOTE(gabehabe @ 1 Jul, 2008 - 05:10 AM)

Nope, it works...

I accidentally deleted the station_count declaration though

It checks the difference between the ASCII value, but be warned:
If the user enters A to d, the difference will be wrong... So we need to convert them to upper case, to avoid this problem, right?

cpp

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <math.h>
#include <ctype.h> // toupper()

int main()
{
	char start_station, end_station;
	int station_count;

	printf("Enter your initial station: ");
	scanf("%c", &start_station);
    fflush(stdin);

	printf("Enter your final station: ");
	scanf("%c", &end_station);
    fflush(stdin);

    // convert them to upper case to ensure ASCII math is correct
    start_station = toupper(start_station);
    end_station   = toupper(end_station);

    printf ("You chose %c as your starting position\n", start_station);
    printf ("You chose %c as your destination\n", end_station);

    station_count = start_station - end_station;
	if (station_count < 0)
        station_count = -(station_count);
    printf("\n\nTotal stations travelled : %d\n", station_count);

	return 0;
}

yeah thanks dude! since it gets the value of the ASCII characters, so if the if the first station is A and the second station is D instead of B i would get D-A= 68-65=3 instead if 1, which is still a flaw though.. But never mind that..

You have been a great help, and i appreciate it

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rajesh_strg	1 Jul, 2008 - 06:03 AM Post #8
New D.I.C Head Joined: 1 Jul, 2008 Posts: 9	Hey Dude.......Great ......... Can u try another program..............if u r free..... WAP to print Amstrong numbers form 1 to n. Carry on....................
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polymath	1 Jul, 2008 - 08:05 AM Post #9
D.I.C Regular Joined: 4 Apr, 2008 Posts: 390 Thanked 4 times Dream Kudos: 500 My Contributions	QUOTE(rajesh_strg @ 1 Jul, 2008 - 09:03 AM) Hey Dude.......Great ......... Can u try another program..............if u r free..... WAP to print Amstrong numbers form 1 to n. Carry on.................... One, there are several topics about Armstrong number generators right here at DIC. Search is your friend. Hint, use the % operator to break up a number into its component numbers. Two, we are not a code writing service. QUOTE You Must Show Us Your Code. Is shown inside every posting box whenever you click "add reply" or "New Topic".
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captainhampton	1 Jul, 2008 - 08:28 AM Post #10
D.I.C Addict Joined: 17 Oct, 2007 Posts: 501 Thanked 2 times Dream Kudos: 775 My Contributions	http://www.cplusplus.happycodings.com/Begi...nts/code35.html
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Einherjar	1 Jul, 2008 - 11:55 AM Post #11
D.I.C Head Joined: 10 Feb, 2008 Posts: 73 My Contributions	QUOTE(shangyi @ 1 Jul, 2008 - 08:39 AM) QUOTE(gabehabe @ 1 Jul, 2008 - 05:10 AM) Nope, it works... I accidentally deleted the station_count declaration though It checks the difference between the ASCII value, but be warned: If the user enters A to d, the difference will be wrong... So we need to convert them to upper case, to avoid this problem, right? cpp #define _CRT_SECURE_NO_WARNINGS #include <stdio.h> #include <math.h> #include <ctype.h> // toupper() int main() { char start_station, end_station; int station_count; printf("Enter your initial station: "); scanf("%c", &start_station); fflush(stdin); printf("Enter your final station: "); scanf("%c", &end_station); fflush(stdin); // convert them to upper case to ensure ASCII math is correct start_station = toupper(start_station); end_station = toupper(end_station); printf ("You chose %c as your starting position\n", start_station); printf ("You chose %c as your destination\n", end_station); station_count = start_station - end_station; if (station_count < 0) station_count = -(station_count); printf("\n\nTotal stations travelled : %d\n", station_count); return 0; } yeah thanks dude! since it gets the value of the ASCII characters, so if the if the first station is A and the second station is D instead of B i would get D-A= 68-65=3 instead if 1, which is still a flaw though.. But never mind that.. You have been a great help, and i appreciate it Wait, why would that be a flaw? Isn't that exactly what is supposed to happen?
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gabehabe	1 Jul, 2008 - 12:04 PM Post #12
T3H R0XX0R! Joined: 6 Feb, 2008 Posts: 2,232 Thanked 44 times Dream Kudos: 1450 Expert In: C, C++ My Contributions	That's right, D-A should be 3
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