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drop down forms

 
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drop down forms, getting information from drop down menus
merlinore
post 27 Jun, 2008 - 11:13 AM
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[font=Arial]

<form method="post" action="<?php echo $PHP_SELF;?>">
<select name="playertoedit[]">
<option value="0" <?php
if (empty($playertoedit)) echo "selected";
?>>- select -</option>

<?php
for ($ix=0; $ix<$ii; $ix++)
{ echo " <option value='$firstandlastnamearray[$ix]'";
echo ">",$firstandlastnamearray[$ix],"</option>\n";
}?>

</select>
<br>
<input type="submit" value="submit" name="submit">
</form>

$testx = $_POST['playertoedit'];

/*This should say 'Array' */
echo "Skill sets posted as: .$testx";

this doesn't seem to work
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level1
post 27 Jun, 2008 - 12:22 PM
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QUOTE

$testx = $_POST['playertoedit'];

/*This should say 'Array' */
echo "Skill sets posted as: .$testx";

this doesn't seem to work


Notice this is not php atm. You need to put it inside of <?php ?> tags. Once you do that you will see $testx echoes Array. To retrieve the values of your select you can do $testx[0], etc. Now, really this is not a good way to do things. You should remove the [] from the name of your select. So, your select should just be named playertoedit. Then you can retrieve the value they selected from $testx.

(i.e. just add the php tags and remove the [] from your select and you will be done)
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merlinore
post 27 Jun, 2008 - 01:08 PM
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Hi,
I don't quite understand?



$testx = $_POST['playertoedit'];

is the above to be changed to :

CODE

<?php  
$testx = playertoedit;

/*This should say 'Array' */
echo "Skill sets posted as: .$testx";
?>


THis did not work - an example would help

Thanks
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